isothermal process การใช้

• Isothermal processes are of special interest for ideal gases.
• The reversible isothermal process would probably generate more energy.
• Other issues include the time required for heat transfer, particularly for the isothermal processes.
• Thus, in an isothermal process the internal energy of an ideal gas is constant.
• Newton had assumed an isothermal process, while Laplace, a calorist, treated it as adiabatic.
• Practically, all the heat produced will be utilized throughout all the processes, as it is an adiabatic and isothermal process.
• For example, in thermodynamics the isothermal process explicitly follows the hyperbolic path and work can be interpreted as a hyperbolic angle change.
• At low frequencies, the compression is an isothermal process and \ gamma \ left ( \ omega \ right ) is equal to one.
• This makes sense since all the work done by the cycle is done by the pair of isothermal processes, which are described by " Q = W ".
• An isothermal process, by definition, is a constant temperature process from start to finish, and heat flows in or out of it without a change in temperature anywhere.
• Temperature is the thermodynamic conjugate variable to entropy, thus the conjugate process would be an isothermal process in which the system is thermally " connected " to a constant-temperature heat bath.
• The cycle is consequently composed of adiabatic processes where no heat / caloric  " S = 0 flows and isothermal processes where heat is transferred  " S > 0 but no temperature difference  " T = 0 exist.
• We see that the total amount of work that can be extracted in an isothermal process is limited by the free energy decrease, and that increasing the free energy in a reversible process requires work to be done on the system.
• In order to achieve a near thermodynamic reversible process so that most of the energy is saved in the system and can be retrieved, and losses are kept negligible, a near reversible isothermal process or an isentropic process is desired.
• Assuming that the temperature was increased slowly, you would find that the process path is not straight and no longer isobaric, but would instead undergo an isometric process till the force exceeded that of the frictional force and then would undergo an isothermal process back to an equilibrium state.
• For more accurate information, the height of the highest point, or the max pressure, to surpass the static friction would be proportional to the frictional coefficient and the slop going back down to the normal pressure would be the same as an isothermal process if the temperature was increased at a slow enough rate.
• Without additional context suggesting otherwise, the problem you stated is likely meant to be solved as an isothermal process ( what you did ), but if it was from a course which had just discussed adiabatic expansion ( and the bubble was somehow sufficiently insulated from the surrounding water ) or if it was at the end of a chapter on the temperature profiles of lakes, then other assumptions would likely hold.